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  • In pdb how do you reset the list (l) command line count?

    - by Jorge Vargas
    From PDB (Pdb) help l l(ist) [first [,last]] List source code for the current file. Without arguments, list 11 lines around the current line or continue the previous listing. With one argument, list 11 lines starting at that line. With two arguments, list the given range; if the second argument is less than the first, it is a count. The "continue the previous listing" feature is really nice, but how do you turn it off?

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  • How to effectively execute this cron job?

    - by Lost_in_code
    I have a table with 200 rows. I'm running a cron job every 10 minutes to perform some kind of insert/update operation on the table. The operation needs to be performed only on 5 rows at a time every time the cron job runs. So in first 10 mins records 1-5 are updated, records 5-10 in the 20th minute and so on. When the cron job runs for the 20th time, all the records in the table would have been updated exactly once. This is what is to be achieved at least. And the next cron job should repeat the process again. The problem: is that, every time a cron job runs, the insert/update operation should be performed on N rows (not just 5 rows). So, if N is 100, all records would've been updated by just 2 cron jobs. And the next cron job would repeat the process again. Here's an example: This is the table I currently have (200 records). Every time a cron job executes, it needs to pick N records (which I set as a variable in PHP) and update the time_md5 field with the current time's MD5 value. +---------+-------------------------------------+ | id | time_md5 | +---------+-------------------------------------+ | 10 | 971324428e62dd6832a2778582559977 | | 72 | 1bd58291594543a8cc239d99843a846c | | 3 | 9300278bc5f114a290f6ed917ee93736 | | 40 | 915bf1c5a1f13404add6612ec452e644 | | 599 | 799671e31d5350ff405c8016a38c74eb | | 56 | 56302bb119f1d03db3c9093caf98c735 | | 798 | 47889aa559636b5512436776afd6ba56 | | 8 | 85fdc72d3b51f0b8b356eceac710df14 | | .. | ....... | | .. | ....... | | .. | ....... | | .. | ....... | | 340 | 9217eab5adcc47b365b2e00bbdcc011a | <-- 200th record +---------+-------------------------------------+ So, the first record(id 10) should not be updated more than once, till all 200 records are updated once - the process should start over once all the records are updated once. I have some idea on how this could be achieved, but I'm sure there are more efficient ways of doing it. Any suggestions?

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  • UIImageView doesn't update with my image

    - by Sheehan Alam
    I am trying to set my image: detailedEventViewController.thumbnail.image = [UIImage imageNamed:@"amnesia.png"]; But the imageview appears blank. amnesia.png is in my resources group. The file exists. Results of my log: 2011-01-08 10:52:32.822 HD Pocket Vacations[25271:207] Image: <UIImage: 0x66203b0> 2011-01-08 10:52:32.823 HD Pocket Vacations[25271:207] dEVC: <DetailedEventViewController: 0x6628340> 2011-01-08 10:52:32.824 HD Pocket Vacations[25271:207] thumbnail: (null)

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  • Arduino variable going blank after first pass.

    - by user541597
    I have an arduino sketch that takes a timet and when that timet is equal to the current time it sets the new timet to timet + 2. For example: char* convert(char* x, String y){ int hour; int minute; sscanf(x, "%d:%d", &hour, &minute); char buf[6]; if (y == "6"){ if (hour > 17){ hour = (hour+6)%24; snprintf(buf, 10, "%d:%d", hour, minute ); }else if (hour < 18){ //hour = hour + 6; minute = (minute + 2); snprintf(buf, 10, "%d:%d", hour, minute); } } if (y == "12"){ if (hour > 11){ hour = (hour+12)%24; snprintf(buf, 10, "%d:%d", hour, minute ); } else if (hour < 12){ hour = hour + 12; snprintf(buf, 10, "%d:%d", hour, minute); } } if (y == "24"){ hour = (hour+24)%24; snprintf(buf, 10, "%d:%d", hour, minute ); } return buf; } sketch starts for example at 1:00am timet is set to 1:02, at system time 1:02 timet == system time my loops looks like this: if (timet == currenttime){ timet = convert(timet) } From this now when ever I check the value of timet it should equal 1:04, however I am getting the correct value at the first run after the execution of convert however everytime after that my timet value is blank. I tried changing the code instead of using the if loop I only run the convert function when I send for example t through the serial monitor, this works fine and outputs the correct timet after the execution of the convert function, So I figured the problem is in the if loop... Any ideas?

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  • Creating and Saving an Excel File

    - by Kris
    I have the following code that creates a new Excel file in my C# code behind. When I attempt to save the file I would like the user to select the location of the save. In Method #1, I can save the file my using the workbook SaveCopyAs without prompting the user for a location. This saves one file to the C:\Temp directory. Method #2 will save the file in my Users\Documents folder, then prompt the user to select the location and save a second copy. How can I eliminate the first copy from saving in the Users\Documents folder? Excel.Application oXL; Excel._Workbook oWB; Excel._Worksheet oSheet; Excel.Range oRng; try { //Start Excel and get Application object. oXL = new Excel.Application(); oXL.Visible = false; //Get a new workbook. oWB = (Excel._Workbook)(oXL.Workbooks.Add(Missing.Value)); oSheet = (Excel._Worksheet)oWB.ActiveSheet; // ***** oSheet.Cells[2, 6] = "Ship To:"; oSheet.get_Range("F2", "F2").Font.Bold = true; oSheet.Cells[2, 7] = sShipToName; oSheet.Cells[3, 7] = sAddress; oSheet.Cells[4, 7] = sCityStateZip; oSheet.Cells[5, 7] = sContactName; oSheet.Cells[6, 7] = sContactPhone; oSheet.Cells[9, 1] = "Shipment No:"; oSheet.get_Range("A9", "A9").Font.Bold = true; oSheet.Cells[9, 2] = sJobNumber; oSheet.Cells[9, 6] = "Courier:"; oSheet.get_Range("F9", "F9").Font.Bold = true; oSheet.Cells[9, 7] = sCarrierName; oSheet.Cells[11, 1] = "Requested Delivery Date:"; oSheet.get_Range("A11", "A11").Font.Bold = true; oSheet.Cells[11, 2] = sRequestDeliveryDate; oSheet.Cells[11, 6] = "Courier Acct No:"; oSheet.get_Range("F11", "F11").Font.Bold = true; oSheet.Cells[11, 7] = sCarrierAcctNum; // ***** Method #1 //oWB.SaveCopyAs(@"C:\Temp\" + sJobNumber +".xls"); Method #2 oXL.SaveWorkspace(sJobNumber + ".xls"); } catch (Exception theException) { String errorMessage; errorMessage = "Error: "; errorMessage = String.Concat(errorMessage, theException.Message); errorMessage = String.Concat(errorMessage, " Line: "); errorMessage = String.Concat(errorMessage, theException.Source); }

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  • WPF, convert Path.DataProperty to Segment objects

    - by user275587
    I was wondering if there was a tool to convert a path data like "M 0 0 l 10 10" to it's equivalent line/curve segment code. Currently I'm using: string pathXaml = "<Path xmlns=\"http://schemas.microsoft.com/winfx/2006/xaml/presentation\" xmlns:x=\"http://schemas.microsoft.com/winfx/2006/xaml\" Data=\"M 0 0 l 10 10\"/>"; Path path = (Path)System.Windows.Markup.XamlReader.Load(pathXaml); It appears to me that calling XamlParser is much slower than explicitly creating the line segments. However converting a lot of paths by hand is very tedious.

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  • What does size really mean in geom_point?

    - by Jonas Stein
    In both plots the points look different, but why? mya <- data.frame(a=1:100) ggplot() + geom_path(data=mya, aes(x=a, y=a, colour=2, size=seq(0.1,10,0.1))) + geom_point(data=mya, aes(x=a, y=a, colour=1, size=1)) + theme_bw() + theme(text=element_text(size=11)) ggplot() + geom_path(data=mya, aes(x=a, y=a, colour=2, size=1)) + geom_point(data=mya, aes(x=a, y=a, colour=1, size=1)) + theme_bw() + theme(text=element_text(size=11))

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  • Select count() max() Date HELP!!! mysql oracle

    - by DAVID
    Hi guys i have a table with shifts history along with emp ids im using this code to retrieve a list of employees and their total shifts by specifying the range to count from: SELECT ope_id, count(ope_id) FROM operator_shift WHERE ope_shift_date >=to_date( '01-MAR-10','dd-mon-yy') and ope_shift_date <= to_date('31-MAR-10','dd-mon-yy') GROUP BY OPE_ID which gives OPE_ID COUNT(OPE_ID) 1 14 2 7 3 6 4 6 5 2 6 5 7 2 8 1 9 2 10 4 10 rows selected. NOW how do i choose the employee with the highest no of shifts under the specified range date, please this is really important

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  • In R, how to get powers of ten in bold font in a plot label?

    - by wfoolhill
    I want to have "10^4 points" in bold as my x-axis label. I know how to make a simple label in bold: plot(1:10, xlab="") mtext(text="10 points", side=1, font=2, line=3) Thanks to this answer, I know how to make a label with a power of ten but nothing is in bold: mtext(text=expression(paste(10^4, " points")), side=1, font=2, line=3) Thanks to this answer, I also know how to make a label with a Greek letter in bold: mtext(text=expression(bold(paste(beta, "=", 10^1, " points"))), side=1, line=3) But still the power of ten is not in bold! It doesn't work either with bquote: mtext(text=bquote(bold(10^1~points)), side=1, line=3) Any idea? Here are some details about my system. Let me know if you need anything else. > sessionInfo() R version 2.15.0 (2012-03-30) Platform: x86_64-redhat-linux-gnu (64-bit) locale: [1] LC_CTYPE=en_US.UTF-8 LC_NUMERIC=C [3] LC_TIME=en_US.UTF-8 LC_COLLATE=en_US.UTF-8 [5] LC_MONETARY=en_US.UTF-8 LC_MESSAGES=en_US.UTF-8 [7] LC_PAPER=C LC_NAME=C [9] LC_ADDRESS=C LC_TELEPHONE=C [11] LC_MEASUREMENT=en_US.UTF-8 LC_IDENTIFICATION=C attached base packages: [1] stats graphics grDevices utils datasets methods base

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  • -Java- Swing GUI - Moving around components specifically with layouts

    - by Xemiru Scarlet Sanzenin
    I'm making a little test GUI for something I'm making. However, problems occur with the positioning of the panels. public winInit() { super("Chatterbox - Login"); try { UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName()); } catch(ClassNotFoundException e) { } catch (InstantiationException e) { } catch (IllegalAccessException e) { } catch (UnsupportedLookAndFeelException e) { } setSize(300,135); pn1 = new JPanel(); pn2 = new JPanel(); pn3 = new JPanel(); l1 = new JLabel("Username"); l2 = new JLabel("Password"); l3 = new JLabel("Random text here"); l4 = new JLabel("Server Address"); l5 = new JLabel("No address set."); i1 = new JTextField(10); p1 = new JPasswordField(10); b1 = new JButton("Connect"); b2 = new JButton("Register"); b3 = new JButton("Set IP"); l4.setBounds(10, 12, getDim(l4).width, getDim(l4).height); l1.setBounds(10, 35, getDim(l1).width, getDim(l1).height); l2.setBounds(10, 60, getDim(l2).width, getDim(l2).height); l3.setBounds(10, 85, getDim(l3).width, getDim(l3).height); l5.setBounds(l4.getBounds().width + 14, 12, l5.getPreferredSize().width, l5.getPreferredSize().height); l5.setForeground(Color.gray); i1.setBounds(getDim(l1).width + 15, 35, getDim(i1).width, getDim(i1).height); p1.setBounds(getDim(l1).width + 15, 60, getDim(p1).width, getDim(p1).height); b1.setBounds(getDim(l1).width + getDim(i1).width + 23, 34, getDim(b2).width, getDim(b1).height - 5); b2.setBounds(getDim(l1).width + getDim(i1).width + 23, 60, getDim(b2).width, getDim(b2).height - 5); b3.setBounds(getDim(l1).width + getDim(i1).width + 23, 10, etDim(b2).width, getDim(b3).height - 5); b1.addActionListener(clickButton); b2.addActionListener(clickButton); b3.addActionListener(clickButton); pn1.setLayout(new FlowLayout(FlowLayout.RIGHT)); pn2.setLayout(new FlowLayout(FlowLayout.RIGHT)); pn1.add(l1); pn1.add(i1); pn1.add(b1); pn2.add(l2); pn2.add(p1); pn2.add(b2); add(pn1); add(pn2); } I am attempting to use FlowLayout to position the panels in the way desired. I'd use BorderLayout while adding, but the vertical spacing is too far away when I just use directions closest to one another. The output of this code is to create a window, 300,150, place whatever's in the two panels in the exact same spaces. Yes, I realize there's useless code there with setBounds(), but that was just me screwing around with Absolute Positioning, which wasn't working out for me either.

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  • MySQL Query to find consecutive available times of variable lenth

    - by Armaconn
    I have an events table that has user_id, date ('2013-10-01'), time ('04:15:00'), and status_id; What I am looking to find is a solution similar to http://stackoverflow.com/questions/2665574/find-consecutive-rows-calculate-duration but I need I need two additional components: 1) Take date into consideration, so 10/1/2013 at 11:00 PM - 10/2/2013 at 3:00AM. Feel free to just put in a fake date range (like '2013-10-01' to '2013-10-31') 2) Limit output to only include when there are 4+ consecutive times (each event is 15 minutes and I want it to display minimum blocks of an hour, but would also like to be able to switch this restriction to 1.5 hours or some other duration if possible). SUMMARY - Looking for a query that provides the start and end times for a set of events that have the same user_id, status_id, and are in a continuous series based on date and time. For which I can restrict results based on date range and minimum series duration. So the output should have: user_id, date_start, time_start, date_end, time_end, status_id, duration CREATE TABLE `events` ( `event_id` int(11) NOT NULL auto_increment COMMENT 'ID', `user_id` int(11) NOT NULL, `date` date NOT NULL, `time` time NOT NULL, `status_id` int(11) default NULL, PRIMARY KEY (`event_id`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=1568 ; INSERT INTO `events` VALUES(1, 101, '2013-08-14', '23:00:00', 2); INSERT INTO `events` VALUES(2, 101, '2013-08-14', '23:15:00', 2); INSERT INTO `events` VALUES(3, 101, '2013-08-14', '23:30:00', 2); INSERT INTO `events` VALUES(4, 101, '2013-08-14', '23:45:00', 2); INSERT INTO `events` VALUES(5, 101, '2013-08-15', '00:00:00', 2); INSERT INTO `events` VALUES(6, 101, '2013-08-15', '00:15:00', 1); INSERT INTO `events` VALUES(7, 500, '2013-08-14', '23:45:00', 1); INSERT INTO `events` VALUES(8, 500, '2013-08-15', '00:00:00', 1); INSERT INTO `events` VALUES(9, 500, '2013-08-15', '00:15:00', 2); INSERT INTO `events` VALUES(10, 500, '2013-08-15', '00:30:00', 2); INSERT INTO `events` VALUES(11, 500, '2013-08-15', '00:45:00', 1); Desired output row |user_id | date_start | time_start | date_end | time_end | status_id | duration 1 |101 |'2013-08-14'| '23:00:00' |'2013-08-15'|'00:15:00'| 2 | 5 2 |101 |'2013-08-15'| '00:00:15' |'2013-08-15'|'00:30:00'| 1 | 1 3 |500 |'2013-08-14'| '00:23:45' |'2013-08-15'|'00:15:00'| 1 | 2 4 |500 |'2013-08-15'| '00:00:15' |'2013-08-15'|'00:45:00'| 2 | 2 5 |500 |'2013-08-15'| '00:00:45' |'2013-08-15'|'01:00:00'| 2 | 1 *except that rows 2 and 5 wouldn't appear if duration had to be greater than 30 minutes Thanks for any help that you can provide! And please let me know if there is anything I can further clarify!!

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  • join select from multiple row values?

    - by user1869132
    Two tables 1) product -------------------- id | Name | price 1 | p1 | 10 2 | p2 | 20 3 | p3 | 30 2) product_attributes: --------------------------------------------------- id | product_id | attribute_name | attribute_value --------------------------------------------------- 1 | 1 | size | 10 2 | 1 | colour | red 3 | 2 | size | 20 I need to join these two tables. In the where clause I need to match both the two rows attribute values. Is it possible to get the result based on two rows value. Here if size=10 and colour=red. Output should be 1 | p1 | 10 It could be greatly helpful to get a query for this.

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  • Finding the digit root of a number

    - by Jessica M.
    Study question is to find the digit root of a already provided number. The teacher provides us with the number 2638. In order to find the digit root you have to add each digit separately 2 + 6 + 3 + 8 = 19. Then you take the result 19 and add those two digits together 1 + 9 = 10. Do the same thing again 1 + 0 = 1. The digit root is 1. My first step was to use the variable total to add up the number 2638 to find the total of 19. Then I tried to use the second while loop to separate the two digits by using the % I have to try and solve the problem by using basic integer arithmetic (+, -, *, /). 1.Is it necessary and or possible to solve the problem using nested while loops? 2.Is my math correct? 3. As I wrote it here it does not run in Eclipse. Am I using the while loops correctly? import acm.program.*; public class Ch4Q7 extends ConsoleProgram { public void run(){ println("This program attempts to find the digit root of your number: "); int n = readInt("Please enter your number: "); int total = 0; int root = total; while (n > 0 ){ total = total + (n %10); n = (n / 10); } while ( total > 0 ){ root = total; total = ((total % 10) + total / 10); } println("your root should be " + root); } }

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  • How can I set the Jbuttons in a preferred order?

    - by Umzz Mo
    I have a grid of 30 buttons, and I want to have it from left to right then goes down, right to left, down again left to right. Basically the numbering would be as follow: 1 2 3 4 5 6 7 8 9 10 20 19 18 17 16 15 14 13 12 11 21 22 23 24 25 26 27 28 29 30 So if I have a piece on the button 10 and I instruct it to move up 2 bits it would land on 12 not 19. Below is my Code: //Creates the button using the loop, adds it into the panel and frame. JPanel panel = new JPanel(); panel.setLayout(new GridLayout(3,10)); JButton [] buttons = new JButton[30]; for(int i=0;i<30;i++){ buttons[i] = new JButton("label" + i); buttons[i].setBackground(Color.white); //Puts the player 1 piece on button 1,3,5,7,9 and player 2 piece on button 2,4,6,8,10 if (i < 10) { if (i%2 == 0) { buttons[i].setIcon(piece1); } else { buttons[i].setIcon(piece2); } } panel.add(buttons[i]); } frame.add(panel, BorderLayout.CENTER);

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  • Get the count of login datetime and username from the textfile

    - by user2897388
    I am having a textfile with usename, userid, login and logout time. From this textfile I need to get the userid and howmany times that user logged in on that particular date. I am doing this one using C# (.NET) in windows applications. I tried this code but I am getting the whole text into the string strRead. In that strRead I need to get the count of user login basing on date. StreamReader strmrdr = new StreamReader("Logfiles.txt"); string strRead = strmrdr.ReadToEnd(); Username:Rajini||UserId:abc||Userlogintime:10/19/13 12:33:29 PM||UserLogoutTime:10/19/13 12:33:57 PM Username:Rajini||UserId:abc||Userlogintime:10/19/13 12:35:29 PM||UserLogoutTime:10/19/13 12:36:57 PM

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  • How can I draw a hollow rectangle using CreatePen?

    - by LarsTech
    Since using the DrawArc function in GDI+ isn't very accurate when drawing a small rounded rectangle, I am using RoundRect instead. Protected Overrides Sub OnPaint(ByVal e As PaintEventArgs) Dim hDC As IntPtr = e.Graphics.GetHdc Dim rc As New Rectangle(10, 10, 64, 24) Dim hPen As IntPtr = Win32.CreatePen(Win32.PenStyle.PS_SOLID, 0, _ ColorTranslator.ToWin32(Color.Green)) Dim hOldPen As IntPtr = Win32.SelectObject(hDC, hPen) Call Win32.RoundRect(hDC, rc.Left, rc.Top, rc.Right, rc.Bottom, 10, 10) Win32.SelectObject(hDC, hOldPen) Win32.DeleteObject(hPen) e.Graphics.ReleaseHdc(hDC) MyBase.OnPaint(e) End Sub This will draw a nice rounded rectangle, but it will also fill it with a white brush, erasing what I don't want to have erased. How can I draw this without erasing the inside of the rectangle?

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  • gem install giving error that I can't change permissions.. chown and chmod not working

    - by user2321289
    so I am trying to install hmac gem install ruby-hmac -v 0.4.0 I am getting the following error message: You don't have write permissions into the /opt/rbenv/versions/1.9.3-p448/lib/ruby/gems/1.9.1 directory So the output from ls -l is as such: ubuntu@ip-10-38-121-211:~/workspace/cf-release$ sudo ls -l /opt/rbenv/versions/1.9.3-p448/lib/ruby/gems/ I perform a chown on this directory: sudo chown -R ubuntu:ubuntu /opt/rbenv/versions/1.9.3-p448/lib/ruby/gems/ Try to install the gem: ubuntu@ip-10-38-121-211:~/workspace/cf-release$ sudo chown -v ubuntu:ubuntu /opt/rbenv/versions/1.9.3-p448/lib/ruby/gems/ ownership of `/opt/rbenv/versions/1.9.3-p448/lib/ruby/gems/' retained as ubuntu:ubuntu I do another ls -l on the directory: ubuntu@ip-10-38-121-211:~/workspace/cf-release$ ls -l /opt/rbenv/versions/1.9.3-p448/lib/ruby/gems/ total 4 d--------- 8 ubuntu ubuntu 4096 Nov 1 20:43 1.9.1 Doing a chmod 777 to make the directory writeable: ubuntu@ip-10-38-121-211:~/workspace/cf-release$ sudo chmod -v 777 /opt/rbenv/versions/1.9.3-p448/lib/ruby/gems/ mode of `/opt/rbenv/versions/1.9.3-p448/lib/ruby/gems/' retained as 0777 (rwxrwxrwx) ubuntu@ip-10-38-121-211:~/workspace/cf-release$ ls -l /opt/rbenv/versions/1.9.3-p448/lib/ruby/gems/ total 4 d--------- 8 ubuntu ubuntu 4096 Nov 1 20:43 1.9.1 Any idea as to why this would be acting up like this? I am at a loss here.. any help appreciated

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  • Using list() to extract a data.table inside of a function

    - by Nathan VanHoudnos
    I must admit that the data.table J syntax confuses me. I am attempting to use list() to extract a subset of a data.table as a data.table object as described in Section 1.4 of the data.table FAQ, but I can't get this behavior to work inside of a function. An example: require(data.table) ## Setup some test data set.seed(1) test.data <- data.table( X = rnorm(10), Y = rnorm(10), Z = rnorm(10) ) setkey(test.data, X) ## Notice that I can subset the data table easily with literal names test.data[, list(X,Y)] ## X Y ## 1: -0.8356286 -0.62124058 ## 2: -0.8204684 -0.04493361 ## 3: -0.6264538 1.51178117 ## 4: -0.3053884 0.59390132 ## 5: 0.1836433 0.38984324 ## 6: 0.3295078 1.12493092 ## 7: 0.4874291 -0.01619026 ## 8: 0.5757814 0.82122120 ## 9: 0.7383247 0.94383621 ## 10: 1.5952808 -2.21469989 I can even write a function that will return a column of the data.table as a vector when passed the name of a column as a character vector: get.a.vector <- function( my.dt, my.column ) { ## Step 1: Convert my.column to an expression column.exp <- parse(text=my.column) ## Step 2: Return the vector return( my.dt[, eval(column.exp)] ) } get.a.vector( test.data, 'X') ## [1] -0.8356286 -0.8204684 -0.6264538 -0.3053884 0.1836433 0.3295078 ## [7] 0.4874291 0.5757814 0.7383247 1.5952808 But I cannot pull a similar trick for list(). The inline comments are the output from the interactive browser() session. get.a.dt <- function( my.dt, my.column ) { ## Step 1: Convert my.column to an expression column.exp <- parse(text=my.column) ## Step 2: Enter the browser to play around browser() ## Step 3: Verity that a literal X works: my.dt[, list(X)] ## << not shown >> ## Step 4: Attempt to evaluate the parsed experssion my.dt[, list( eval(column.exp)] ## Error in `rownames<-`(`*tmp*`, value = paste(format(rn, right = TRUE), (from data.table.example.R@1032mCJ#7) : ## length of 'dimnames' [1] not equal to array extent return( my.dt[, list(eval(column.exp))] ) } get.a.dt( test.data, "X" ) What am I missing? Update: Due to some confusion as to why I would want to do this I wanted to clarify. My use case is when I need to access a data.table column when when I generate the name. Something like this: set.seed(2) test.data[, X.1 := rnorm(10)] which.column <- 'X' new.column <- paste(which.column, '.1', sep="") get.a.dt( test.data, new.column ) Hopefully that helps.

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  • No more memory available in Mathematica, Fit the parameters of system of differential equation

    - by user1058051
    I encountered a memory problem in Mathematica, when I tried to process my experimental data. It's a system of two differential equations and I need to find most suitable parameters. Unfortunately I am not a Pro in Mathematica, so the program used a lot of memory, when the parameter epsilon is more than 0.4. When it less than 0.4, the program work properly. The command 'historylength = 0' and attempts to reduce the Accuracy Goal and WorkingPrecision didn`t help. I can't use ' clear Cache ', because there isnt a circle. I'm trying to understand what mistakes I made, and how I may limit the memory usage. I have already bought extra-RAM, now its 4GB, and now I haven't free memory-slots in motherboard Remove["Global`*"]; T=13200; L = 0.085; e = 0.41; v = 0.000557197; q = 0.1618; C0 = 0.0256; R = 0.00075; data = {{L,600,0.141124587},{L,1200,0.254134509},{L,1800,0.342888644}, {L,2400,0.424476295},{L,3600,0.562844542},{L,4800,0.657111356}, {L,6000,0.75137817},{L,7200,0.815876516},{L,8430,0.879823594}, {L,9000,0.900771775},{L,13200,1}}; model[(De_)?NumberQ, (Kf_)?NumberQ, (Y_)?NumberQ] := model[De, Kf, Y] = yeld /.Last[Last[ NDSolve[{ v (Ci^(1,0))[z,t]+(Ci^(0,1))[z,t]== -((3 (1-e) Kf (Ci[z,t]-C0))/ (R e (1-(R Kf (1-R/r[z,t]))/De))), (r^(0,1))[z,t]== (R^2 Kf (Ci[z,t]-C0))/ (q r[z,t]^2 (1-(R Kf (1-R/r[z,t]))/De)), (yeld^(0,1))[z,t]== Y*(v e Ci[z,t])/(L q (1-e)), r[z,0]==R, Ci[z,0]==0, Ci[0,t]==0, yeld[z,0]==0}, {r[z,t],Ci[z,t],yeld},{z,0,L},{t,0,T}]]] fit = FindFit[data, {model[De, Kf, Y][z, t], {Y > 0.97, Y < 1.03, Kf > 10^-6, Kf < 10^-4, De > 10^-13, De < 10^-9}}, {{De,7*10^-13}, {Kf, 10^-5}, {Y, 1}}, {z, t}, Method -> NMinimize] data = {{600,0.141124587},{1200,0.254134509},{1800,0.342888644}, {2400,0.424476295},{3600,0.562844542},{4800,0.657111356}, {6000,0.75137817},{7200,0.815876516},{8430,0.879823594}, {9000,0.900771775},{13200,1}}; YYY = model[ De /. fit[[1]], Kf /. fit[[2]], Y /. fit[[3]]]; Show[Plot[Evaluate[YYY[L,t]],{t,0,T},PlotRange->All], ListPlot[data,PlotStyle->Directive[PointSize[Medium],Red]]] the link on the .nb file http://www.4shared.com/folder/249TSjlz/_online.html

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  • help with t-sql data aggregation

    - by stackoverflowuser
    Based on the following table Area S1 S2 S3 S4 -------------------- A1 5 10 20 0 A2 11 19 15 20 A3 0 0 0 20 I want to generate an output that will give the number of columns not having "0". So the output would be Area S1 S2 S3 S4 Count ------------------------- A1 5 10 20 0 3 A2 11 19 15 20 4 A3 0 0 0 20 1

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  • Show/hide rows with jquery

    - by Mike
    Hi I am using some modified code from another post. Basically I want to switch between showing 10 rows of a table to showing all rows (50 for example). I have got it to show from 10 rows to all, however what I need to do now is code it so that if I click the div again it toggles or resets back to showing 10 rows. <script type="text/javascript"> var numShown = 10; // Initial rows shown & index var numRows = $('tbody').find('tr').length; var numLeft = numRows - numShown; $(document).ready(function(){ // Hide rows and add clickable div $('tbody') .find('tr:gt(' + (numShown - 1) + ')').hide().end() $('#table_wrapper').after('<div id="more">Show all offers <span>(' + numLeft + ' more)</span></div>'); $('#more').click(function(){ numShown = numShown + numRows; // 7 + 1 = 8 $('tbody').find('tr:lt('+numShown+')').show(); $("#more").html("Show top 10 offers"); }) }) </script>

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  • How can I delete a specific element in priority queue?

    - by Yuan
    import java.util.*; public class test4 { public static void main(String[] args){ PriorityQueue[] P = new PriorityQueue[10]; P[1] = new PriorityQueue<ClassEntry>(); P[1].add(new ClassEntry(1.2,1)); P[1].add(new ClassEntry(1.5,2)); P[1].add(new ClassEntry(1.2,3)); P[1].add(new ClassEntry(10,4)); P[1].remove(new ClassEntry(10,4));//I can't delete this object??? System.out.println(P[1].size()); ClassEntry ce = (ClassEntry) P[1].peek(); System.out.println(P[1].size()); System.out.println(ce.sim+"\t"+ce.index); } } Why i can't delete (10,4)? Can somebody teach how to implement...thanks!

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